A container containing O2(.g.) was connected to another empty container as shown in following diagram and maintained at given temperature: Then calculate total pressure (in mmHg ) in container (after connecting container for long time). Given R=0.0821 L-atmK- 1mol- 1

Question

A container containing O2(.g.) was connected to another empty container as shown in following diagram and maintained at given temperature: <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/c-trsvurv1yg2ycgqr.jpg" /> Then calculate total pressure (in mmHg ) in container (after connecting container for long time). Given R=0.0821 L-atmK- 1mol- 1 (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Let X mole of O2 in container II (1 - x)(R × 400/16 . 42)=(xR × 300/8 . 21) x=(2/5) ∴ PT=(2/5)× (R × 300/8 . 21)=(6/5)atm=(6/5)× 760=912mmHg

Q. A container containing $O_{2} (g)$ was connected to another empty container as shown in following diagram and maintained at given temperature :

Then calculate total pressure (in $mm H g$ ) in container (after connecting container for long time). Given $R = 0.0821$ $L - a t m K^{- 1} m o l^{- 1}$

Let $X$ mole of $O_{2}$ in container $II$
$(1 - x) \frac{R \times 400}{16.42} = \frac{x R \times 300}{8.21}$
$x = \frac{2}{5}$
$∴ P_{T} = \frac{2}{5} \times \frac{R \times 300}{8.21} = \frac{6}{5} a t m = \frac{6}{5} \times 760 = 912 mm H g$

Q. A container containing O2​(g) was connected to another empty container as shown in following diagram and maintained at given temperature : Then calculate total pressure (in mmHg ) in container (after connecting container for long time). Given R=0.0821 L−atmK−1mol−1

Let X mole of O2​ in container II (1−x)16.42R×400​=8.21xR×300​ x=52​ ∴PT​=52​×8.21R×300​=56​atm=56​×760=912mmHg

Let $X$ mole of $O_{2}$ in container $II$
$(1 - x) \frac{R \times 400}{16.42} = \frac{x R \times 300}{8.21}$
$x = \frac{2}{5}$
$∴ P_{T} = \frac{2}{5} \times \frac{R \times 300}{8.21} = \frac{6}{5} a t m = \frac{6}{5} \times 760 = 912 mm H g$