Question

A conducting sphere of radius R has surface charge density o. The electric potential on its surface is

• A. $\frac{\sigma R}{{\epsilon }_0}$
• B. ${\epsilon }_0\sigma R$
• C. $\frac{R}{{\epsilon }_0\sigma }$
• D. $\frac{\sigma }{{\epsilon }_{0}R}$

Answer 1

Answer: (A)

Electric potential on the surface of conducting sphere of radius R is given by
$V=\frac{1}{4\pi {\epsilon }_{0}R}\frac{q}{R}(\because q=4\pi R^2\sigma )$
$\therefore V=\frac{\sigma R}{{\epsilon }_0}$