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  4. A conducting sphere of radius R has surface charge density o. The electric potential on its surface is

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Q. A conducting sphere of radius R has surface charge density o. The electric potential on its surface is

COMEDKCOMEDK 2006Electrostatic Potential and Capacitance

Solution:

Electric potential on the surface of conducting sphere of radius R is given by
$ V = \frac{1}{4 \pi \varepsilon_0 R} \frac{q}{R} \, \, \, \, \, (\because \, q = 4 \pi R^2 \sigma) $
$ \therefore \, V= \frac{\sigma R}{\varepsilon_0} $