A conducting rod of length 1m rotates in vertical plane about one of its ends with angular velocity 5 radians per second. If the horizontal component of the earth’s magnetic field is 0.2× 10- 4T , find the e.m.f. developed between the two ends of the rod:

Question

A conducting rod of length 1m rotates in vertical plane about one of its ends with angular velocity 5 radians per second. If the horizontal component of the earth&rsquo;s magnetic field is 0.2× 10- 4T , find the e.m.f. developed between the two ends of the rod: (A) 5μ V (B) 50μ V (C) 5mV (D) 50mV

Tardigrade Admin · Accepted Answer

ei n d=(1/2)Bω l2=(1/2)× (. 0 .2 × (10)- 4 .)× 5× (. 1 .)2=5× (10)- 5V=50μ V

Q. A conducting rod of length $1 m$ rotates in vertical plane about one of its ends with angular velocity $5$ radians per second. If the horizontal component of the earth’s magnetic field is $0.2 \times 1 0^{- 4} T$ , find the e.m.f. developed between the two ends of the rod:

$5 μ V$

$50 μ V$

$5 mV$

$50 mV$

$e_{in d} = \frac{1}{2} B ω l^{2} = \frac{1}{2} \times (0.2 \times (10)^{- 4}) \times 5 \times (1)^{2} = 5 \times (10)^{- 5} V = 50 μ V$

Q. A conducting rod of length 1m rotates in vertical plane about one of its ends with angular velocity 5 radians per second. If the horizontal component of the earth’s magnetic field is 0.2×10−4T , find the e.m.f. developed between the two ends of the rod:

5μV

50μV

5mV

50mV