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  4. A conducting rod of length 1m rotates in vertical plane about one of its ends with angular velocity 5 radians per second. If the horizontal component of the earth’s magnetic field is 0.2× 10- 4T , find the e.m.f. developed between the two ends of the rod:

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Q. A conducting rod of length $1m$ rotates in vertical plane about one of its ends with angular velocity $5$ radians per second. If the horizontal component of the earth’s magnetic field is $0.2\times 10^{- 4}T$ , find the e.m.f. developed between the two ends of the rod:

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Solution:

$e_{i n d}=\frac{1}{2}B\omega l^{2}=\frac{1}{2}\times \left(\right. 0 .2 \times \left(10\right)^{- 4} \left.\right)\times 5\times \left(\right. 1 \left.\right)^{2}=5\times \left(10\right)^{- 5}V=50\mu V$