A conducting loop having a capacitor is moving outward from the magnetic field. Which plate of the capacitor will be positive?

Question

A conducting loop having a capacitor is moving outward from the magnetic field. Which plate of the capacitor will be positive? (A) Plate A (B) Plate B (C) Both plate A and plate B (D) None

Tardigrade Admin · Accepted Answer

Crosses (x) linked with the loop are decreasing, so induced current in it is clockwise, i.e., from B arrow A. Hence, electrons flow from plate A to B, so plate A becomes positively charged.

Q. A conducting loop having a capacitor is moving outward from the magnetic field. Which plate of the capacitor will be positive?

Plate A

Plate B

Both plate A and plate B

None

Crosses (x) linked with the loop are decreasing, so induced current in it is clockwise, i.e., from $B \to A$ . Hence, electrons flow from plate $A$ to $B$ , so plate $A$ becomes positively charged.

Q. A conducting loop having a capacitor is moving outward from the magnetic field. Which plate of the capacitor will be positive?

Plate A

Plate B

Both plate A and plate B

None

Crosses (x) linked with the loop are decreasing, so induced current in it is clockwise, i.e., from B→A. Hence, electrons flow from plate A to B, so plate A becomes positively charged.

Crosses (x) linked with the loop are decreasing, so induced current in it is clockwise, i.e., from $B \to A$ . Hence, electrons flow from plate $A$ to $B$ , so plate $A$ becomes positively charged.