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Q. A conducting loop having a capacitor is moving outward from the magnetic field. Which plate of the capacitor will be positive?Physics Question Image

Electromagnetic Induction

Solution:

Crosses (x) linked with the loop are decreasing, so induced current in it is clockwise, i.e., from $B \rightarrow A$. Hence, electrons flow from plate $A$ to $B$, so plate $A$ becomes positively charged.