A conducting circular loop of radius r carries a constant current I. It is placed in a uniform magnetic field B such that B is perpendicular to the plane of the loop. The magnetic force acting on the loop is

Question

A conducting circular loop of radius r carries a constant current I. It is placed in a uniform magnetic field B such that B is perpendicular to the plane of the loop. The magnetic force acting on the loop is (A) B I R (B) 2 π (BIR) (C) zero (D) π (B I R )

Tardigrade Admin · Accepted Answer

F=∫ B bari bard l=0 as ∫ bard l=0

Q. A conducting circular loop of radius $r$ carries a constant current $I$ . It is placed in a uniform magnetic field $B$ such that $B$ is perpendicular to the plane of the loop. The magnetic force acting on the loop is

B I R

$2 π$ (BIR)

zero

$π$ (B I R )

$F = \int B \overset{ˉ}{i} \overset{ˉ}{d} l = 0$ as $\int \overset{ˉ}{d} l = 0$

Q. A conducting circular loop of radius r carries a constant current I. It is placed in a uniform magnetic field B such that B is perpendicular to the plane of the loop. The magnetic force acting on the loop is

B I R

2π (BIR)

zero

π (B I R )

F=∫Biˉdˉl=0 as ∫dˉl=0

Q. A conducting circular loop of radius $r$ carries a constant current $I$ . It is placed in a uniform magnetic field $B$ such that $B$ is perpendicular to the plane of the loop. The magnetic force acting on the loop is

$2 π$ (BIR)

$π$ (B I R )

$F = \int B \overset{ˉ}{i} \overset{ˉ}{d} l = 0$ as $\int \overset{ˉ}{d} l = 0$