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  4. A conducting circular loop of radius r carries a constant current I. It is placed in a uniform magnetic field B such that B is perpendicular to the plane of the loop. The magnetic force acting on the loop is

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Q. A conducting circular loop of radius $r$ carries a constant current $I$. It is placed in a uniform magnetic field $B$ such that $B$ is perpendicular to the plane of the loop. The magnetic force acting on the loop is

Solution:

$F=\int B \bar{i} \bar{d} l=0$ as $\int \bar{d} l=0$