A conductivity cell has been calibrated with a 0.01 M 1: 1 electrolyte solution (specific conductance, k=1.25 × 10-3 S cm-1) in the cell and the measured resistance was 800 ohms at 25°C. The constant will be

Question

A conductivity cell has been calibrated with a 0.01 M 1: 1 electrolyte solution (specific conductance, k=1.25 × 10-3 S cm-1) in the cell and the measured resistance was 800 ohms at 25°C. The constant will be (A) 1.02 cm-1 (B) 0.102 cm-1 (C) 1.00 cm-1 (D) 0.5 cm-1

Tardigrade Admin · Accepted Answer

Given, kappa=1.25 × 10-3 S cm -1 ρ =(1/ K )=(1/1.25 × 10-3) S -1 cm From R=ρ (I/A) 800=(1/1.25 × 10-3) × (1/A) (where, (l/A)= cell constant) ∴ (1/A)=800 × 1.25 × 10-3 =1 cm -1

Q. A conductivity cell has been calibrated with a $0.01 M 1 : 1$ electrolyte solution (specific conductance, $k = 1.25 \times 1 0^{- 3} S c m^{- 1}$ ) in the cell and the measured resistance was $800 o hm s$ at $2 5^{\circ} C$ . The constant will be

$1.02 c m^{- 1}$

$0.102 c m^{- 1}$

$1.00 c m^{- 1}$

$0.5 c m^{- 1}$

Q. A conductivity cell has been calibrated with a 0.01M1:1 electrolyte solution (specific conductance, k=1.25×10−3Scm−1) in the cell and the measured resistance was 800ohms at 25∘C. The constant will be

1.02cm−1

0.102cm−1

1.00cm−1

0.5cm−1

Given, κ=1.25×10−3Scm−1 ρ=K1​=1.25×10−31​S−1cm From R=ρAI​ 800=1.25×10−31​×A1​ (where, Al​= cell constant) ∴A1​=800×1.25×10−3 =1cm−1

Q. A conductivity cell has been calibrated with a $0.01 M 1 : 1$ electrolyte solution (specific conductance, $k = 1.25 \times 1 0^{- 3} S c m^{- 1}$ ) in the cell and the measured resistance was $800 o hm s$ at $2 5^{\circ} C$ . The constant will be

$1.02 c m^{- 1}$

$0.102 c m^{- 1}$

$1.00 c m^{- 1}$

$0.5 c m^{- 1}$