1. Tardigrade
  2. Question
  3. Chemistry
  4. A conductivity cell has been calibrated with a 0.01 M 1: 1 electrolyte solution (specific conductance, k=1.25 × 10-3 S cm-1) in the cell and the measured resistance was 800 ohms at 25°C. The constant will be

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A conductivity cell has been calibrated with a $0.01 \,M \,1 : 1$ electrolyte solution (specific conductance, $k=1.25 \times 10^{-3}\, S\, cm^{-1}$) in the cell and the measured resistance was $800\, ohms$ at $25^{\circ}C$. The constant will be

WBJEEWBJEE 2013Electrochemistry

Solution:

Given, $ \kappa=1.25 \times 10^{-3} S cm ^{-1} $
$\rho =\frac{1}{ K }=\frac{1}{1.25 \times 10^{-3}} S ^{-1} \,cm$
From $ R=\rho \frac{I}{A}$
$800=\frac{1}{1.25 \times 10^{-3}} \times \frac{1}{A}$
(where, $\frac{l}{A}=$ cell constant)
$\therefore \frac{1}{A}=800 \times 1.25 \times 10^{-3}$
$=1 \,cm ^{-1} $