A compound X, of boron reacts with NH 3 on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating BF 3 with Lithium aluminium hydride. The compounds X an Y are represented by the formulas.

Question

A compound X, of boron reacts with NH 3 on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating BF 3 with Lithium aluminium hydride. The compounds X an Y are represented by the formulas. (A) B2 H6, B3 N3 H6 (B) B2 O3, B3 N3 H6 (C) B2 F3, B3 N3 H6 (D) B3 N3 H6, B2 H6

Tardigrade Admin · Accepted Answer

BF 3 xrightarrow[-LiF,-AlF3] LiAlH 4 underset( X ) B 2 H 6 xrightarrow[-H2] NH 3 / Δ underset( Y ) B 3 N 3 H 6 (X) ⇒ B2 H6 (Diborane) (Y) ⇒ B3 N3 H6 (Borazine or inorganic benzene)

Q. A compound $X$ , of boron reacts with $N H_{3}$ on heating to give another compound $Y$ which is called inorganic benzene. The compound $X$ can be prepared by treating $B F_{3}$ with Lithium aluminium hydride. The compounds $X$ an $Y$ are represented by the formulas.

$B_{2} H_{6}, B_{3} N_{3} H_{6}$

$B_{2} O_{3}, B_{3} N_{3} H_{6}$

$B_{2} F_{3}, B_{3} N_{3} H_{6}$

$B_{3} N_{3} H_{6}, B_{2} H_{6}$

$B F_{3} L i A l H_{4} - L i F, - A l F_{3} (X) B_{2} H_{6} N H_{3} /Δ - H_{2} (Y) B_{3} N_{3} H_{6}$
$(X) \Rightarrow B_{2} H_{6}$ (Diborane)
$(Y) \Rightarrow B_{3} N_{3} H_{6}$ (Borazine or inorganic benzene)

Q. A compound X, of boron reacts with NH3​ on heating to give another compound Y which is called inorganic benzene. The compound X can be prepared by treating BF3​ with Lithium aluminium hydride. The compounds X an Y are represented by the formulas.

B2​H6​,B3​N3​H6​

B2​O3​,B3​N3​H6​

B2​F3​,B3​N3​H6​

B3​N3​H6​,B2​H6​