Question

A compound was found to contain nitrogen $28$ g and oxygen $80$ g. The formula of the compound is ( $N=14$ , $O=16$ )

• A. $NO$
• B. $N_2{O}_3$
• C. $N_2{O}_5$
• D. $N_2{O}_4$

Answer 1

Answer: (C)

Moles of $N=\frac{28}{14}=2$
Moles of $O=\frac{80}{16}=5$
So, the formula of oxide will be $N_2{O}_5$