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Q. A compound was found to contain nitrogen $28$ g and oxygen $80$ g. The formula of the compound is ( $N=14$ , $O=16$ )

NTA AbhyasNTA Abhyas 2022

Solution:

Moles of $N=\frac{28}{14}=2$
Moles of $O=\frac{80}{16}=5$
So, the formula of oxide will be $N_{2}O_{5}$