A compound MX2 has observed and normal molar masses 65.6 and 164 respectively. Calculate the apparent degree of ionization of MX2

Question

A compound MX2 has observed and normal molar masses 65.6 and 164 respectively. Calculate the apparent degree of ionization of MX2 (A) 75% (B) 85% (C) 65% (D) 25%

Tardigrade Admin · Accepted Answer

i=(N o r m a l m o l a r m a s s/O b s e r v e d m o l a r m a s s) =(164/65.6)=2.5 α =(i - 1/n - 1) n=3 (number of ions) α = (2.5 - 1/3 - 1) = (1.5/2) = 0.75 So percentage ionization of MX2 will be 75%.

Q. A compound $M X_{2}$ has observed and normal molar masses 65.6 and 164 respectively. Calculate the apparent degree of ionization of $M X_{2}$

75%

85%

65%

25%

$i = \frac{N or ma l m o l a r ma ss}{O b ser v e d m o l a r ma ss}$

$= \frac{164}{65.6} = 2.5$

$α = \frac{i - 1}{n - 1}$

$n = 3$ (number of ions)

$α = \frac{2.5 - 1}{3 - 1} = \frac{1.5}{2} = 0.75$

So percentage ionization of $M X_{2}$ will be 75%.

Q. A compound MX2​ has observed and normal molar masses 65.6 and 164 respectively. Calculate the apparent degree of ionization of MX2​

75%

85%

65%

25%

i=ObservedmolarmassNormalmolarmass​ =65.6164​=2.5 α=n−1i−1​ n=3 (number of ions) α=3−12.5−1​=21.5​=0.75 So percentage ionization of MX2​ will be 75%.

Q. A compound $M X_{2}$ has observed and normal molar masses 65.6 and 164 respectively. Calculate the apparent degree of ionization of $M X_{2}$

$i = \frac{N or ma l m o l a r ma ss}{O b ser v e d m o l a r ma ss}$

$= \frac{164}{65.6} = 2.5$

$α = \frac{i - 1}{n - 1}$

$n = 3$ (number of ions)

$α = \frac{2.5 - 1}{3 - 1} = \frac{1.5}{2} = 0.75$

So percentage ionization of $M X_{2}$ will be 75%.