A compound contains C =90 % and H =10 %. Empirical formula of the compound is

Question

A compound contains C =90 % and H =10 %. Empirical formula of the compound is (A) C 3 H 10 (B) CH 2 (C) C 3 H 2 (D) C 3 H 4

Tardigrade Admin · Accepted Answer

Elements No. of moles Simple ratio C =90 % 90/12 = 7.5 7.5 / 7.5 =1 × 3=3 H =10 % 10/1 = 10 10 / 7.5 =1.33 × 3=4 ∴ Empirical formula = C 3 H 4

Elements	No. of moles	Simple ratio
$C = 90%$	$90/12 = 7.5$	$7.5/7.5 = 1 \times 3 = 3$
$H = 10%$	$10/1 = 10$	$10/7.5 = 1.33 \times 3 = 4$

Q. A compound contains $C = 90%$ and $H = 10%$ . Empirical formula of the compound is