Q. A compound contains $C =90 \%$ and $H =10 \%$. Empirical formula of the compound is
Organic Chemistry – Some Basic Principles and Techniques
Solution:
Elements
No. of moles
Simple ratio
$C =90 \%$
$90/12 = 7.5 $
$7.5 / 7.5 =1 \times 3=3$
$H =10 \%$
$10/1 = 10 $
$10 / 7.5 =1.33 \times 3=4$
$\therefore$ Empirical formula $= C _{3} H _{4}$
| Elements | No. of moles | Simple ratio |
|---|---|---|
| $C =90 \%$ | $90/12 = 7.5 $ | $7.5 / 7.5 =1 \times 3=3$ |
| $H =10 \%$ | $10/1 = 10 $ | $10 / 7.5 =1.33 \times 3=4$ |