A compound contains 69.5 % oxygen and 30.5 % nitrogen and its molecular weight is 92. The formula of the compound is

Question

A compound contains 69.5 % oxygen and 30.5 % nitrogen and its molecular weight is 92. The formula of the compound is (A)  N2O  (B)  NO2  (C)  N2O4  (D)  N2O5

Tardigrade Admin · Accepted Answer

Since compound contains 30.5 % of nitrogen and 69.5 % of oxygen by weight, N: O=(30.5/14): (69.5/16)=1: 2 Empirical Formula is NO 2. Molecular weight is 92 . X=(92/46)=2 Molecular formula =( text Empirical formula )X Molecular formula = N 2 O 4

Q. A compound contains $69.5%$ oxygen and $30.5%$ nitrogen and its molecular weight is $92$ . The formula of the compound is

$N_{2} O$

$N O_{2}$

$N_{2} O_{4}$

$N_{2} O_{5}$

Since compound contains $30.5%$ of nitrogen and $69.5%$ of oxygen by weight, $N : O = \frac{30.5}{14} : \frac{69.5}{16} = 1 : 2$
Empirical Formula is $N O_{2}$ .
Molecular weight is $92$ .
$X = \frac{92}{46} = 2$
Molecular formula $= (Empirical formula)_{X}$
Molecular formula $= N_{2} O_{4}$

Q. A compound contains 69.5% oxygen and 30.5% nitrogen and its molecular weight is 92. The formula of the compound is

N2​O

NO2​

N2​O4​

N2​O5​