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Q.
A compound contains $69.5\%$ oxygen and $30.5\%$ nitrogen and its molecular weight is $92$. The formula of the compound is
Uttarkhand PMTUttarkhand PMT 2007
Solution:
Since compound contains $30.5 \%$ of nitrogen and $69.5 \%$ of oxygen by weight, $N: O=\frac{30.5}{14}: \frac{69.5}{16}=1: 2$
Empirical Formula is $NO _{2}$.
Molecular weight is $92$ .
$X=\frac{92}{46}=2$
Molecular formula $=(\text { Empirical formula })_{X}$
Molecular formula $= N _{2} O _{4}$