A compound contains 4.07 % hydrogen, 24.27 % carbon and 71.65 % chlorine. Its molar mass is 98.96 g mol-1. What will be the molecular formula of the substance?

Question

A compound contains 4.07 % hydrogen, 24.27 % carbon and 71.65 % chlorine. Its molar mass is 98.96 g mol-1. What will be the molecular formula of the substance? (A) CH2Cl (B) C2H4Cl2 (C) CHCl3 (D) CH2Cl2

Tardigrade Admin · Accepted Answer

Element % of Element Relative number of mole H 4.07 (4.07/1) = 4.07 ≈ 4 C 24 . 27 (24.27/12) ≈ 2 Cl 71 .65 (71 . 65/35.5) ≈ 2 ∴ Empirical formula = C2H4Cl2

Q. A compound contains $4.07%$ hydrogen, $24.27%$ carbon and $71.65%$ chlorine. Its molar mass is $98.96 g m o l^{- 1}$ . What will be the molecular formula of the substance?

$C H_{2} Cl$

$C_{2} H_{4} C l_{2}$

$C H C l_{3}$

$C H_{2} C l_{2}$

Element % of Element Relative number of mole

H 4.07 $\frac{4.07}{1} = 4.07 \approx 4$

C 24 . 27 $\frac{24.27}{12} \approx 2$

Cl 71 .65 $\frac{71.65}{35.5} \approx 2$

$∴$ Empirical formula $= C_{2} H_{4} C l_{2}$

Element	% of Element	Relative number of mole
H	4.07	$\frac{4.07}{1} = 4.07 \approx 4$
C	24 . 27	$\frac{24.27}{12} \approx 2$
Cl	71 .65	$\frac{71.65}{35.5} \approx 2$

Q. A compound contains 4.07% hydrogen, 24.27% carbon and 71.65% chlorine. Its molar mass is 98.96gmol−1. What will be the molecular formula of the substance?

CH2​Cl

C2​H4​Cl2​

CHCl3​

CH2​Cl2​