Q. A compound contains $4.07 \%$ hydrogen, $24.27 \%$ carbon and $71.65 \%$ chlorine. Its molar mass is $98.96 \,g \,mol^{-1}$. What will be the molecular formula of the substance?
Some Basic Concepts of Chemistry
Solution:
Element
% of Element
Relative number of mole
H
4.07
$\frac{4.07}{1} = 4.07 \approx 4$
C
24 . 27
$\frac{24.27}{12} \approx 2$
Cl
71 .65
$\frac{71 . 65}{35.5} \approx 2$
$\therefore $ Empirical formula $= C_2H_4Cl_2$
| Element | % of Element | Relative number of mole |
|---|---|---|
| H | 4.07 | $\frac{4.07}{1} = 4.07 \approx 4$ |
| C | 24 . 27 | $\frac{24.27}{12} \approx 2$ |
| Cl | 71 .65 | $\frac{71 . 65}{35.5} \approx 2$ |