A compound ( 60 gm ) on analysis gave C =24 gm , H =4 gm, and O =32 gm. Its empirical formula is:

Question

A compound ( 60 gm ) on analysis gave C =24 gm , H =4 gm, and O =32 gm. Its empirical formula is: (A) C 2 H 2 O (B) C 2 H 4 O 2 (C) CH 2 O (D) CH 2 O 2

Tardigrade Admin · Accepted Answer

C: H: O (24/12): (4/1): (32/16) 2: 4: 2 EF = C 2 H 4 O 2

Q. A compound ( $60 g m$ ) on analysis gave $C = 24 g m, H = 4 g m$ , and $O = 32 g m$ . Its empirical formula is:

$C_{2} H_{2} O$

$C_{2} H_{4} O_{2}$

$C H_{2} O$

$C H_{2} O_{2}$

$C : H : O$
$\frac{24}{12} : \frac{4}{1} : \frac{32}{16}$
$2 : 4 : 2$
$EF = C_{2} H_{4} O_{2}$

Q. A compound ( 60gm ) on analysis gave C=24gm,H=4gm, and O=32gm. Its empirical formula is:

C2​H2​O

C2​H4​O2​

CH2​O

CH2​O2​