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  3. Chemistry
  4. A compound ( 60 gm ) on analysis gave C =24 gm , H =4 gm, and O =32 gm. Its empirical formula is:

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Q. A compound ( $60 gm$ ) on analysis gave $C =24 \,gm , H =4 \,gm$, and $O =32 \,gm$. Its empirical formula is:

Organic Chemistry – Some Basic Principles and Techniques

Solution:

$C : H : O$
$\frac{24}{12}: \frac{4}{1}: \frac{32}{16}$
$2: 4: 2$
$EF = C _2 H _4 O _2$