A common emitter transistor amplifier has a current gain of 50. If the load resistance is 4 kΩ and input resistance is 500 Ω, the voltage gain of the amplifier is

Question

A common emitter transistor amplifier has a current gain of 50. If the load resistance is 4 kΩ and input resistance is 500 Ω, the voltage gain of the amplifier is (A) 100 (B) 200 (C) 300 (D) 400

Tardigrade Admin · Accepted Answer

Here, Î² = 50, RL = 4 kΩ = 4 Ã 103 Ω Ri = 500 kΩ Voltage gain, A upsilon = β (RL/Ri) = 50×(4×103/500) = 400

Q. A common emitter transistor amplifier has a current gain of 50. If the load resistance is $4 k Ω$ and input resistance is $500 Ω$ , the voltage gain of the amplifier is

100

200

300

400

Here, $β = 50, R_{L} = 4 k Ω = 4 \times 1 0^{3} Ω R_{i} = 500 k Ω$
Voltage gain, $A_{υ} = β \frac{R _{L}}{R _{i}} = 50 \times \frac{4 \times 1 0 ^{3}}{500} = 400$

Q. A common emitter transistor amplifier has a current gain of 50. If the load resistance is 4kΩ and input resistance is 500Ω, the voltage gain of the amplifier is

100

200

300

400

Here, β=50,RL​=4kΩ=4×103ΩRi​=500kΩ Voltage gain, Aυ​=βRi​RL​​=50×5004×103​=400

Q. A common emitter transistor amplifier has a current gain of 50. If the load resistance is $4 k Ω$ and input resistance is $500 Ω$ , the voltage gain of the amplifier is

Here, $β = 50, R_{L} = 4 k Ω = 4 \times 1 0^{3} Ω R_{i} = 500 k Ω$
Voltage gain, $A_{υ} = β \frac{R _{L}}{R _{i}} = 50 \times \frac{4 \times 1 0 ^{3}}{500} = 400$