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Q. A common emitter transistor amplifier has a current gain of 50. If the load resistance is $4\,k\Omega$ and input resistance is $500\,\Omega$, the voltage gain of the amplifier is

Semiconductor Electronics: Materials Devices and Simple Circuits

Solution:

Here, $β = 50,\, R_{L} = 4\,k\Omega = 4 × 10^{3} \Omega R_i = 500\,k\Omega$
Voltage gain, $A_{\upsilon} = \beta \frac{R_{L}}{R_{i}} = 50\times\frac{4\times10^{3}}{500} = 400$