A coin is tossed twice. Then, the probability that atleast one tail occurs is

Question

A coin is tossed twice. Then, the probability that atleast one tail occurs is (A) (1/4) (B) (1/2) (C) (1/3) (D) (3/4)

Tardigrade Admin · Accepted Answer

The sample space is S= H H, H T, T H, T T Let E be the event of getting atleast one tail E= H T, T H, T T ∴ Required probability P =( text Number of favourable outcomes / text Total number of outcomes ) =(n(E)/n(S))=(3/4)

Q. A coin is tossed twice. Then, the probability that atleast one tail occurs is

$\frac{1}{4}$

$\frac{1}{2}$

$\frac{1}{3}$

$\frac{3}{4}$

The sample space is $S = {HH, H T, T H, TT}$
Let $E$ be the event of getting atleast one tail
$E = {H T, T H, TT}$
$∴$ Required probability $P$
$= \frac{Number of favourable outcomes}{Total number of outcomes}$
$= \frac{n ( E )}{n ( S )} = \frac{3}{4}$