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  4. A coin is tossed twice. Then, the probability that atleast one tail occurs is

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Q. A coin is tossed twice. Then, the probability that atleast one tail occurs is

Probability

Solution:

The sample space is $S=\{H H, H T, T H, T T\}$
Let $E$ be the event of getting atleast one tail
$E=\{H T, T H, T T\}$
$\therefore$ Required probability $P$
$=\frac{\text { Number of favourable outcomes }}{\text { Total number of outcomes }} $
$ =\frac{n(E)}{n(S)}=\frac{3}{4}$