A coil of self-inductance 50 henry is joined to the terminals of a battery of e.m.f. 2 volts through a resistance of 10 ohm and a steady current is flowing through the circuit. If the battery is now disconnected, the time in which the current will decay to 1 / e of its steady value is

Question

A coil of self-inductance 50 henry is joined to the terminals of a battery of e.m.f. 2 volts through a resistance of 10 ohm and a steady current is flowing through the circuit. If the battery is now disconnected, the time in which the current will decay to 1 / e of its steady value is (A) 500 seconds (B) 50 seconds (C) 5 seconds (D) 0.5 seconds

Tardigrade Admin · Accepted Answer

Time in which the current will decay to (1/e) of its steady value is t=τ=(L/R)=(50/10)=5 s

Q. A coil of self-inductance $50$ henry is joined to the terminals of a battery of e.m.f. $2$ volts through a resistance of $10 o hm$ and a steady current is flowing through the circuit. If the battery is now disconnected, the time in which the current will decay to $1/ e$ of its steady value is

500 seconds

50 seconds

5 seconds

0.5 seconds

Time in which the current will decay to $\frac{1}{e}$ of its steady value is $t = τ = \frac{L}{R} = \frac{50}{10} = 5 s$

Q. A coil of self-inductance 50 henry is joined to the terminals of a battery of e.m.f. 2 volts through a resistance of 10ohm and a steady current is flowing through the circuit. If the battery is now disconnected, the time in which the current will decay to 1/e of its steady value is