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  4. A coil of self-inductance 50 henry is joined to the terminals of a battery of e.m.f. 2 volts through a resistance of 10 ohm and a steady current is flowing through the circuit. If the battery is now disconnected, the time in which the current will decay to 1 / e of its steady value is

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Q. A coil of self-inductance $50$ henry is joined to the terminals of a battery of e.m.f. $2$ volts through a resistance of $10\, ohm$ and a steady current is flowing through the circuit. If the battery is now disconnected, the time in which the current will decay to $1 / e$ of its steady value is

Electromagnetic Induction

Solution:

Time in which the current will decay to $\frac{1}{e}$ of its steady value is $t=\tau=\frac{L}{R}=\frac{50}{10}=5\, s$