A closely wounded circular coil of radius 5 cm produces a magnetic field of 37.68 × 10-4 T at its center. The current through the coil is A. [Given, number of turns in the coil is 100 and π=3.14]

Question

A closely wounded circular coil of radius 5 cm produces a magnetic field of 37.68 × 10-4 T at its center. The current through the coil is A. [Given, number of turns in the coil is 100 and π=3.14] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

B text centre =(N μ0 1/2 R) 37.68 × 10-4=(100 × 4 π × 10-7 × I /2 × 5 × 10-2) I =3 A

Q. A closely wounded circular coil of radius $5 c m$ produces a magnetic field of $37.68 \times 1 0^{- 4} T$ at its center. The current through the coil is ____ $A$ .
[Given, number of turns in the coil is $100$ and $π = 3.14]$

$B_{centre} = \frac{N μ _{0} 1}{2 R}$
$37.68 \times 1 0^{- 4} = \frac{100 \times 4 π \times 1 0 ^{- 7} \times I}{2 \times 5 \times 1 0 ^{- 2}}$
$I = 3 A$

Q. A closely wounded circular coil of radius 5cm produces a magnetic field of 37.68×10−4T at its center. The current through the coil is ____A. [Given, number of turns in the coil is 100 and π=3.14]

Bcentre ​=2RNμ0​1​ 37.68×10−4=2×5×10−2100×4π×10−7×I​ I=3A

Q. A closely wounded circular coil of radius $5 c m$ produces a magnetic field of $37.68 \times 1 0^{- 4} T$ at its center. The current through the coil is ____ $A$ .
[Given, number of turns in the coil is $100$ and $π = 3.14]$

$B_{centre} = \frac{N μ _{0} 1}{2 R}$
$37.68 \times 1 0^{- 4} = \frac{100 \times 4 π \times 1 0 ^{- 7} \times I}{2 \times 5 \times 1 0 ^{- 2}}$
$I = 3 A$