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Q. A closely wounded circular coil of radius $5 \,cm$ produces a magnetic field of $37.68 \times 10^{-4} T$ at its center. The current through the coil is ____$A$.
[Given, number of turns in the coil is $100$ and $\pi=3.14]$

JEE MainJEE Main 2022Moving Charges and Magnetism

Solution:

$ B_{\text {centre }}=\frac{N \mu_0 1}{2 R} $
$ 37.68 \times 10^{-4}=\frac{100 \times 4 \pi \times 10^{-7} \times I }{2 \times 5 \times 10^{-2}} $
$ I =3 A $