Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
A chemical reaction was carried out at 300 K and 280 K. The rate constants were found to be k1 and k2 respectively. Then
Q. A chemical reaction was carried out at
300
K
and
280
K
. The rate constants were found to be
k
1
and
k
2
respectively. Then
5858
198
VITEEE
VITEEE 2011
Report Error
A
k
2
=
4
k
1
B
k
2
=
2
k
1
C
k
2
=
0.25
k
1
D
k
2
=
0.5
k
1
Solution:
For every
1
0
∘
rise in temperture, Rate gets double. Hence, in this case rate constant will become four time. (d) i.e.,
k
1
=
4
k
2
k
2
=
0.25
k
1
as the Rise in temperature given is
2
0
∘
C