Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
A chemical reaction was carried out at 300 K and 280 K. The rate constants were found to be k1 and k2 respectively. Then
Question Error Report
Question is incomplete/wrong
Question not belongs to this Chapter
Answer is wrong
Solution is wrong
Answer & Solution is not matching
Spelling mistake
Image missing
Website not working properly
Other (not listed above)
Error description
Thank you for reporting, we will resolve it shortly
Back to Question
Thank you for reporting, we will resolve it shortly
Q. A chemical reaction was carried out at $300\, K$ and $280\, K$. The rate constants were found to be $k_1$ and $k_2$ respectively. Then
VITEEE
VITEEE 2011
A
$k_2 = 4k_1$
B
$k_2 = 2k_1$
C
$k_2 = 0.25\,k_1$
D
$k_2 = 0.5\,k_1$
Solution:
For every $10^{\circ}$ rise in temperture, Rate gets double. Hence, in this case rate constant will become four time. (d) i.e.,
$k_{1} = 4k_{2}$
$k_{2} = 0.25k_{1}$
as the Rise in temperature given is $20^{\circ}C$