A charged particle moving along +ve x-direction with a velocity v enters a region where there is a uniform magnetic field B 0(- hat k ), from x =0 to x = d. The particle gets deflected at an angle θ from its initial path. The specific charge of the particle is

Question

A charged particle moving along +ve x-direction with a velocity v enters a region where there is a uniform magnetic field B 0(- hat k ), from x =0 to x = d. The particle gets deflected at an angle θ from its initial path. The specific charge of the particle is (A) (v cos θ/ Bd ) (B) (v tan θ/ Bd ) (C) ( v / Bd ) (D) ( v sin θ/ Bd )

Tardigrade Admin · Accepted Answer

sin θ=(d / R) d=R sin θ=(m v/q B) sin θ ⇒ (q/m)=(v sin θ/B d)

Q. A charged particle moving along +ve $x$ -direction with a velocity v enters a region where there is a uniform magnetic field $B_{0} (- \hat{k})$ , from $x = 0$ to $x = d$ . The particle gets deflected at an angle $θ$ from its initial path. The specific charge of the particle is

$\frac{v c o s θ}{B d}$

$\frac{v t a n θ}{B d}$

$\frac{v}{B d}$

$\frac{v s i n θ}{B d}$

$sin θ = (d / R)$
$d = R sin θ = \frac{m v}{qB} sin θ$
$\Rightarrow \frac{q}{m} = \frac{v s i n θ}{B d}$

Q. A charged particle moving along +ve x-direction with a velocity v enters a region where there is a uniform magnetic field B0​(−k^), from x=0 to x=d. The particle gets deflected at an angle θ from its initial path. The specific charge of the particle is

Bdvcosθ​

Bdvtanθ​

Bdv​

Bdvsinθ​