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Q. A charged particle moving along +ve $x$-direction with a velocity v enters a region where there is a uniform magnetic field $B _0(-\hat{ k })$, from $x =0$ to $x = d$. The particle gets deflected at an angle $\theta$ from its initial path. The specific charge of the particle isPhysics Question Image

Moving Charges and Magnetism

Solution:

$\sin \theta=(d / R)$
$d=R \sin \theta=\frac{m v}{q B} \sin \theta $
$\Rightarrow \frac{q}{m}=\frac{v \sin \theta}{B d}$