A charge Q placed at the centre of a metallic spherical shell with inner and outer radii R1 and R2 respectively. The normal component of the electric field at any point on the Gaussian surface with radius between R1 and R2 will be

Question

A charge Q placed at the centre of a metallic spherical shell with inner and outer radii R1 and R2 respectively. The normal component of the electric field at any point on the Gaussian surface with radius between R1 and R2 will be (A) Zero (B) (Q/4 π R12) (C) (Q/4 π R22) (D) (Q/4 π (R1 - R2)2)

Tardigrade Admin · Accepted Answer

The induced charges will appear at the inner and outer surface of the metallic spherical shell. Also there is no charge in between the metal of the shell. So, the normal component of the electric field at any point on the Gaussian surface with radius between R1 and R2 will be zero.

Q. A charge $Q$ placed at the centre of a metallic spherical shell with inner and outer radii $R_{1}$ and $R_{2}$ respectively. The normal component of the electric field at any point on the Gaussian surface with radius between $R_{1}$ and $R_{2}$ will be

Zero

$\frac{Q}{4 π R _{1}^{2}}$

$\frac{Q}{4 π R _{2}^{2}}$

$\frac{Q}{4 π ( R _{1} - R _{2} ) ^{2}}$

The induced charges will appear at the inner and outer surface of the metallic spherical shell. Also there is no charge in between the metal of the shell. So, the normal component of the electric field at any point on the Gaussian surface with radius between $R_{1}$ and $R_{2}$ will be zero.

Q. A charge Q placed at the centre of a metallic spherical shell with inner and outer radii R1​ and R2​ respectively. The normal component of the electric field at any point on the Gaussian surface with radius between R1​ and R2​ will be

Zero

4πR12​Q​

4πR22​Q​

4π(R1​−R2​)2Q​

The induced charges will appear at the inner and outer surface of the metallic spherical shell. Also there is no charge in between the metal of the shell. So, the normal component of the electric field at any point on the Gaussian surface with radius between R1​ and R2​ will be zero.

Q. A charge $Q$ placed at the centre of a metallic spherical shell with inner and outer radii $R_{1}$ and $R_{2}$ respectively. The normal component of the electric field at any point on the Gaussian surface with radius between $R_{1}$ and $R_{2}$ will be

$\frac{Q}{4 π R _{1}^{2}}$

$\frac{Q}{4 π R _{2}^{2}}$

$\frac{Q}{4 π ( R _{1} - R _{2} ) ^{2}}$

The induced charges will appear at the inner and outer surface of the metallic spherical shell. Also there is no charge in between the metal of the shell. So, the normal component of the electric field at any point on the Gaussian surface with radius between $R_{1}$ and $R_{2}$ will be zero.