Question

A charge $Q$ placed at the centre of a metallic spherical shell with inner and outer radii $R_{1}$ and $R_{2}$ respectively. The normal component of the electric field at any point on the Gaussian surface with radius between $R_{1}$ and $R_{2}$ will be

• A. Zero
• B. $\frac{Q}{4 \pi R_{1}^{2}}$
• C. $\frac{Q}{4 \pi R_{2}^{2}}$
• D. $\frac{Q}{4 \pi \left(R_{1} - R_{2}\right)^{2}}$

Answer 1

Answer: (A)

The induced charges will appear at the inner and outer surface of the metallic spherical shell. Also there is no charge in between the metal of the shell. So, the normal component of the electric field at any point on the Gaussian surface with radius between $R_{1}$ and $R_{2}$ will be zero.