A charge particle having charge q=1 C and mass 0.25 kg is projected from origin as shown in figure in x-y plane magnetic field of 1 T is present perpendicular to plane. Find speed v (in m/s ) so that particle can pass through point A(2 , 0).

Question

A charge particle having charge q=1 C and mass 0.25 kg is projected from origin as shown in figure in x-y plane magnetic field of 1 T is present perpendicular to plane. Find speed v (in m/s ) so that particle can pass through point A(2 , 0). <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-ptukrsdtlui2e97h.jpg" /> (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-ptukrsdtlui22nme.jpg" /> 2=2R sinθ 2=2(m v/q B) sinθ v=(q B/m sin θ )=8

Q. A charge particle having charge $q = 1 C$ and mass $0.25 k g$ is projected from origin as shown in figure in $x - y$ plane magnetic field of $1 T$ is present perpendicular to plane. Find speed $v$ (in $m / s$ ) so that particle can pass through point $A (2, 0) .$

$2 = 2 R sin θ$
$2 = 2 \frac{m v}{qB} sin θ$
$v = \frac{qB}{m s i n θ} = 8$

Q. A charge particle having charge q=1C and mass 0.25kg is projected from origin as shown in figure in x−y plane magnetic field of 1T is present perpendicular to plane. Find speed v (in m/s ) so that particle can pass through point A(2,0).

2=2Rsinθ 2=2qBmv​sinθ v=msinθqB​=8

Q. A charge particle having charge $q = 1 C$ and mass $0.25 k g$ is projected from origin as shown in figure in $x - y$ plane magnetic field of $1 T$ is present perpendicular to plane. Find speed $v$ (in $m / s$ ) so that particle can pass through point $A (2, 0) .$

$2 = 2 R sin θ$
$2 = 2 \frac{m v}{qB} sin θ$
$v = \frac{qB}{m s i n θ} = 8$