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Q. A charge particle having charge $q=1\,C$ and mass $0.25\,kg$ is projected from origin as shown in figure in $x-y$ plane magnetic field of $1\,T$ is present perpendicular to plane. Find speed $v$ (in $m/s$ ) so that particle can pass through point $A\left(2 , 0\right).$
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
$2=2R\sin\theta $
$2=2\frac{m v}{q B}\sin\theta $
$v=\frac{q B}{m \sin \theta }=8$