A chain is on a frictionless table with one fifth of its length hanging over the edge. If the chain has length L and mass M, the work required to be done to pull the hanging part back onto the table is

Question

A chain is on a frictionless table with one fifth of its length hanging over the edge. If the chain has length L and mass M, the work required to be done to pull the hanging part back onto the table is (A) (M g L/5) (B) (M g L/50) (C) (M g L/18) (D) (M g L/10)

Tardigrade Admin · Accepted Answer

(1/5) part is hanging, so C.M. is (L/10) length below the table W=(m/5)(8) (L/10)=(M g L/50)

Q. A chain is on a frictionless table with one fifth of its length hanging over the edge. If the chain has length $L$ and mass $M$ , the work required to be done to pull the hanging part back onto the table is

$\frac{M gL}{5}$

$\frac{M gL}{50}$

$\frac{M gL}{18}$

$\frac{M gL}{10}$

$\frac{1}{5}$ part is hanging, so C.M. is $\frac{L}{10}$ length below the table
$W = \frac{m}{5} (8) \frac{L}{10} = \frac{M gL}{50}$

Q. A chain is on a frictionless table with one fifth of its length hanging over the edge. If the chain has length L and mass M, the work required to be done to pull the hanging part back onto the table is

5MgL​

50MgL​

18MgL​

10MgL​