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Q. A chain is on a frictionless table with one fifth of its length hanging over the edge. If the chain has length $L$ and mass $M$, the work required to be done to pull the hanging part back onto the table is

Work, Energy and Power

Solution:

$\frac{1}{5}$ part is hanging, so C.M. is $\frac{L}{10}$ length below the table
$W=\frac{m}{5}(8) \frac{L}{10}=\frac{M g L}{50}$