A certain sample of cuprous sulphide is found to have the composition Cu1 . 92S1 . 00 because of incorporation of Cu2 + and Cu+ ions in the crystal then ratio of Cu2 + and Cu+ ions is:

Question

A certain sample of cuprous sulphide is found to have the composition Cu1 . 92S1 . 00 because of incorporation of Cu2 + and Cu+ ions in the crystal then ratio of Cu2 + and Cu+ ions is: (A) 0.08:1.00 (B) 1:23 (C) 1:24 (D) 1:1

Tardigrade Admin · Accepted Answer

Cu1 . 92S1 . 00 <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-xz0thvqpxgkaokfw.jpg" /> on charge balancing (x)+(192 - x)2=200⇒ x=184 (Cu+/Cu+ 2)=(x/192 - x)=(184/8)=(23/1)

Q. A certain sample of cuprous sulphide is found to have the composition $C u_{1.92} S_{1.00}$ because of incorporation of $C u^{2 +}$ and $C u^{+}$ ions in the crystal then ratio of $C u^{2 +}$ and $C u^{+}$ ions is:

$0.08 : 1.00$

$1 : 23$

$1 : 24$

$1 : 1$

$C u_{1.92} S_{1.00}$

on charge balancing $(x) + (192 - x) 2 = 200 \Rightarrow x = 184$
$\frac{C u ^{+}}{C u ^{+ 2}} = \frac{x}{192 - x} = \frac{184}{8} = \frac{23}{1}$

Q. A certain sample of cuprous sulphide is found to have the composition Cu1.92​S1.00​ because of incorporation of Cu2+ and Cu+ ions in the crystal then ratio of Cu2+ and Cu+ ions is:

0.08:1.00

1:23

1:24

1:1