A certain electric motor wire that carry a current of 4 amp is perpendicular to a magnetic field of 0.8 T. What is the force on each cm of the wire?

Question

A certain electric motor wire that carry a current of 4 amp is perpendicular to a magnetic field of 0.8 T. What is the force on each cm of the wire? (A) 0.08 N (B) 0.06 N (C) 0.04 N (D) 0.02 N

Tardigrade Admin · Accepted Answer

Here: current in the wire I=5 amp Length of the wire = 1cm = 0.01 cm Angle between the wire and magnetic field text= 9 text0 texto Magnetic field B = 0.8 tesla Now, force on each cm of wire =IlB sin θ =5× 0.01× 0.8 sin 90o =0.04× 1=0.04 N

Q. A certain electric motor wire that carry a current of 4 amp is perpendicular to a magnetic field of 0.8 T. What is the force on each cm of the wire?

0.08 N

0.06 N

0.04 N

0.02 N

Here: current in the wire $I = 5$ amp Length of the wire = 1cm = 0.01 cm Angle between the wire and magnetic field $= 9 0^{o}$ Magnetic field B = 0.8 tesla Now, force on each cm of wire $= I lB sin θ$ $= 5 \times 0.01 \times 0.8 sin 90^{o}$ $= 0.04 \times 1 = 0.04 N$

Q. A certain electric motor wire that carry a current of 4 amp is perpendicular to a magnetic field of 0.8 T. What is the force on each cm of the wire?

0.08 N

0.06 N

0.04 N

0.02 N

Here: current in the wire I=5 amp Length of the wire = 1cm = 0.01 cm Angle between the wire and magnetic field = 90o Magnetic field B = 0.8 tesla Now, force on each cm of wire =IlBsinθ =5×0.01×0.8sin90o =0.04×1=0.04N

Here: current in the wire $I = 5$ amp Length of the wire = 1cm = 0.01 cm Angle between the wire and magnetic field $= 9 0^{o}$ Magnetic field B = 0.8 tesla Now, force on each cm of wire $= I lB sin θ$ $= 5 \times 0.01 \times 0.8 sin 90^{o}$ $= 0.04 \times 1 = 0.04 N$