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Q. A certain electric motor wire that carry a current of 4 amp is perpendicular to a magnetic field of 0.8 T. What is the force on each cm of the wire?

VMMC MedicalVMMC Medical 2002

Solution:

Here: current in the wire $ I=5 $ amp Length of the wire = 1cm = 0.01 cm Angle between the wire and magnetic field $ \text{= 9}{{\text{0}}^{\text{o}}} $ Magnetic field B = 0.8 tesla Now, force on each cm of wire $ =IlB\sin \theta $ $ =5\times 0.01\times 0.8\sin {{90}^{o}} $ $ =0.04\times 1=0.04\,N $