A certain dye absorbs lights of λ = 400 nm and then fluorescence light of wavelength 500 nm. Assuming that under given condition 40 % of the absorbed energy is re-emitted as fluorescence, calculate the ratio of quanta absorbed to number of quanta emitted out.

Question

A certain dye absorbs lights of λ = 400 nm and then fluorescence light of wavelength 500 nm. Assuming that under given condition 40 % of the absorbed energy is re-emitted as fluorescence, calculate the ratio of quanta absorbed to number of quanta emitted out. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Eabs×(40/100) = E textEmitted nab× (hc/400) ×(40/100) = nem× (hc/500) (nab/nem) = (400/500) ×(100/40) = 2

Q. A certain dye absorbs lights of $λ = 400$ nm and then fluorescence light of wavelength $500$ nm. Assuming that under given condition $40%$ of the absorbed energy is re-emitted as fluorescence, calculate the ratio of quanta absorbed to number of quanta emitted out.

$E_{ab s} \times \frac{40}{100} = E_{Emitted}$
$n_{ab} \times \frac{h c}{400} \times \frac{40}{100} = n_{e m} \times \frac{h c}{500}$
$\frac{n _{ab}}{n _{e m}} = \frac{400}{500} \times \frac{100}{40} = 2$

Q. A certain dye absorbs lights of λ=400 nm and then fluorescence light of wavelength 500 nm. Assuming that under given condition 40% of the absorbed energy is re-emitted as fluorescence, calculate the ratio of quanta absorbed to number of quanta emitted out.

Eabs​×10040​=EEmitted​ nab​×400hc​×10040​=nem​×500hc​ nem​nab​​=500400​×40100​=2

Q. A certain dye absorbs lights of $λ = 400$ nm and then fluorescence light of wavelength $500$ nm. Assuming that under given condition $40%$ of the absorbed energy is re-emitted as fluorescence, calculate the ratio of quanta absorbed to number of quanta emitted out.

$E_{ab s} \times \frac{40}{100} = E_{Emitted}$
$n_{ab} \times \frac{h c}{400} \times \frac{40}{100} = n_{e m} \times \frac{h c}{500}$
$\frac{n _{ab}}{n _{e m}} = \frac{400}{500} \times \frac{100}{40} = 2$