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  3. Chemistry
  4. A certain dye absorbs lights of λ = 400 nm and then fluorescence light of wavelength 500 nm. Assuming that under given condition 40 % of the absorbed energy is re-emitted as fluorescence, calculate the ratio of quanta absorbed to number of quanta emitted out.

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Q. A certain dye absorbs lights of $\lambda = 400$ nm and then fluorescence light of wavelength $500$ nm. Assuming that under given condition $40\%$ of the absorbed energy is re-emitted as fluorescence, calculate the ratio of quanta absorbed to number of quanta emitted out.

Structure of Atom

Solution:

$E_{abs}\times\frac{40}{100} = E_{\text{Emitted}}$
$n_{ab}\times \frac{hc}{400} \times\frac{40}{100} = n_{em}\times \frac{hc}{500}$
$\frac{n_{ab}}{n_{em}} = \frac{400}{500} \times\frac{100}{40} = 2$