A certain current liberate 0.5 g of hydrogen in 2 h. How many grams of copper can be liberated by the same current flowing for the same time in a copper sulphate solution ?

Question

A certain current liberate 0.5 g of hydrogen in 2 h. How many grams of copper can be liberated by the same current flowing for the same time in a copper sulphate solution ? (A) 12.7 gm (B) 15.9 gm (C) 318 gm (D) 63.5 gm

Tardigrade Admin · Accepted Answer

( text W eight of H 2/ text Ew of H 2)=( text W eight of Cu / text Ew of Cu ) (0.5/1)=( x /63.5 / 2) ∴ x =15.875 g ≈ 15.9 g

Q. A certain current liberate 0.5 g of hydrogen in 2 h. How many grams of copper can be liberated by the same current flowing for the same time in a copper sulphate solution ?

12.7 gm

15.9 gm

318 gm

63.5 gm

$\frac{W eight of H _{2}}{Ew of H _{2}} = \frac{W eight of C u}{Ew of C u}$
$\frac{0.5}{1} = \frac{x}{63.5/2}$
$∴ x = 15.875 g \approx 15.9 g$

Q. A certain current liberate 0.5 g of hydrogen in 2 h. How many grams of copper can be liberated by the same current flowing for the same time in a copper sulphate solution ?

12.7 gm

15.9 gm

318 gm

63.5 gm

Ew of H2​ W eight of H2​​= Ew of Cu W eight of Cu​ 10.5​=63.5/2x​ ∴x=15.875g≈15.9g

$\frac{W eight of H _{2}}{Ew of H _{2}} = \frac{W eight of C u}{Ew of C u}$
$\frac{0.5}{1} = \frac{x}{63.5/2}$
$∴ x = 15.875 g \approx 15.9 g$