A certain amount of metal, whose equivalent mass is 28, displaces 0.7 L of H2 at STP from an acid. Mass of the element is

Question

A certain amount of metal, whose equivalent mass is 28, displaces 0.7 L of H2 at STP from an acid. Mass of the element is (A) 1.75 g (B) 0.875 g (C) 3.50 g (D) 7.00 g

Tardigrade Admin · Accepted Answer

Gram equivalent of metal = Gram equivalent of H 2 ( textWeight of metal/ textEquivalent wt. of metal) = moles of H 2 × valency factor ( text Weight /28)=( text given volume /22.4) × 2 ( text Weight /28)=(0.7/22.4) × 2 Weight =1.75 gm

Q. A certain amount of metal, whose equivalent mass is $28$ , displaces $0.7 L$ of $H_{2}$ at STP from an acid. Mass of the element is

$1.75 g$

$0.875 g$

$3.50 g$

$7.00 g$

Gram equivalent of metal $=$ Gram equivalent of $H_{2}$
$\frac{Weight of metal}{Equivalent wt. of metal} =$ moles of $H_{2} \times$ valency factor
$\frac{Weight}{28} = \frac{given volume}{22.4} \times 2$
$\frac{Weight}{28} = \frac{0.7}{22.4} \times 2$
Weight $= 1.75 g m$

Q. A certain amount of metal, whose equivalent mass is 28, displaces 0.7L of H2​ at STP from an acid. Mass of the element is

1.75g

0.875g

3.50g

7.00g