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Q. A certain amount of metal, whose equivalent mass is $28$, displaces $0.7\, L$ of $H_2$ at STP from an acid. Mass of the element is

Some Basic Concepts of Chemistry

Solution:

Gram equivalent of metal $=$ Gram equivalent of $H _{2}$
$\frac{\text{Weight of metal}}{\text{Equivalent wt. of metal}} =$ moles of $H _{2} \times$ valency factor
$\frac{\text { Weight }}{28}=\frac{\text { given volume }}{22.4} \times 2$
$\frac{\text { Weight }}{28}=\frac{0.7}{22.4} \times 2$
Weight $=1.75\, gm$