Question

A cationic colloidal electrolyte forms micelle at $10^{-4}M$ concentration in water. If $1m{m}^3$ solution contains $10^{12}$ micelle structure, then the no. of cations involved in one micelle are $X\times 10$. Find the value of $X$.

Answer 1

Answer: 6

No. of particles of cationic colloidal electrolyte/litre before micelle formation
$=10^{-4}\times 6\times 10^{23}=6\times 10^{19}$
$\therefore$ No. of particles of cationic colloidal electrolyte/mm${}^3$
$=6\times 10^{19}\times 10^{-6}=6\times 10^{13}$
Number of micelles formed $=10^{12}$ /mm${}^3$
$\therefore$ Number of cations in one micelle $=\frac{6\times 10^{13}}{10^{12}}=60$
$=6\times 10$